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10m^2=14-7m
We move all terms to the left:
10m^2-(14-7m)=0
We add all the numbers together, and all the variables
10m^2-(-7m+14)=0
We get rid of parentheses
10m^2+7m-14=0
a = 10; b = 7; c = -14;
Δ = b2-4ac
Δ = 72-4·10·(-14)
Δ = 609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{609}}{2*10}=\frac{-7-\sqrt{609}}{20} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{609}}{2*10}=\frac{-7+\sqrt{609}}{20} $
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